思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
Untrusted Code ─( Syscall )─→ Host Kernel ─( Hardware API )─→ Hardware
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// console.log(canSeePersonsCount([7,6,5,4,3])); // 输出 [4,3,2,1,0]（正确）